The sum of two numbers is 31 and the product is 150
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Answered by
1
Answer:
let x,y be the numbers
x+y=31
xy=150
x=150/y
150/y+y=31
150+y^2=31y
y^2-31y+150=0
y^2-6y-25y+150=0
y(y-6)-25(y-6)=0
(y-6)(y-25)=0
y=6,25
Answered by
3
Answer:
Let the numbers be = a,b
a + b = 31
a = 31 - b ... (i)
ab = 150 ... (ii)
(i) in (ii):
=> 31b - b^2 - 150 = 0
=> b^2 - 31b + 150 = 0
=> b = 6, 25
a = 31 - b
a = 25, 6
Numbers = 6 and 25
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