The sum of two numbers is 32 and their difference is 22. Find the 2 numbers
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0
Answer:
Let the two numbers be x and y
Accto question= x+y=32(1)
and x-y=22(2)
from equation (1) x=32-y(3)
putting value of x in equation 2
32-y-y=22
32-22=2y
10=2y
y=5
Now putting value of y in equation 3
x=32-5=27
Hence value of two numbers is 27 and 5
Answered by
6
Let the two numbers be x and y.
Given,
x + y = 32
x = 32 - y.... (I)
x - y = 22
32 - y - y = 22
- 2y = 22 - 32
y = -10 / - 2
y = 5....(II)
Putting the value of y in equation (I), we have
x = 32 - 5
x = 27
Therefore, the two values are 27 and 5 respectively.
Hope it helps.
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