The sum of two numbers is 324 and their HCF is 9. Find the numbers.
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Let the two numbers be 'x' and 'y' respectively.then,
x+y=324
9 is their HCF
so each no. must be divisible by 9, where x and y are coprime.
so let x=9a and y= 9b ;
now, 9a + 9b=216
a + b =324/9
a + b=36
There are two pairs (x, y) which satisfy the condition, (13,23) and (5,31). The possible answers are (117, 207) and (45, 279).
x+y=324
9 is their HCF
so each no. must be divisible by 9, where x and y are coprime.
so let x=9a and y= 9b ;
now, 9a + 9b=216
a + b =324/9
a + b=36
There are two pairs (x, y) which satisfy the condition, (13,23) and (5,31). The possible answers are (117, 207) and (45, 279).
Amitava:
But the answer is (315,9)
Answered by
2
Answer:
Let the two numbers be 'x' and 'y' respectively.then,
x+y=324
9 is their HCF
so each no. must be divisible by 9, where x and y are coprime.
so let x=9a and y= 9b ;
now, 9a + 9b=216
a + b =324/9
a + b=36
There are two pairs (x, y) which satisfy the condition, (13,23) and (5,31). The possible answers are (117, 207) and (45, 279).
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