The sum of two numbers is 345678 if one number is sixteen thousand sixteen greater than the other number what is the greatest number
Answers
Answered by
42
let the numbers be a and b.
given.
a-b = 16016
so b= a - 16016
also a+b = 345678
a + a - 16016 = 345678
2a = 345678+16016
2a = 361694
a = 361694/2
a = 180847
greatest number is a
given.
a-b = 16016
so b= a - 16016
also a+b = 345678
a + a - 16016 = 345678
2a = 345678+16016
2a = 361694
a = 361694/2
a = 180847
greatest number is a
Answered by
28
Answer:
The greatest number is 180847
Step-by-step explanation:
Let first number be x
Given that one number is sixteen thousand sixteen greater than the other number
⇒ Other number = x + 16016
Also, The sum of both the numbers is 34568
So, x + x + 16016 = 345678
⇒ 2x + 16016 = 345678
⇒ 2x = 329662
⇒ x = 164831
Other number = x + 16016
⇒ Other number = 180847
Now, 164831 < 180847
Hence, The greatest number is 180847
Similar questions