Question

the sum of two numbers is 36 and one number exceeds another by 8. find the numbers step by step ​

Answer 1

Answer:

Given :-

• Sum of two numbers = 36
• One number exceeds by 8

To Find :-

Number

Solution :-

Let the smaller number be x and greater number be x + 8

$\dag {\mathfrak {\underline{According \: to \: question}}}$

$\sf \mapsto \: 36 = x + 8 + x$

$\sf \mapsto \: 36 = 2x + 8$

$\sf \mapsto \: 36 - 8 = 2x$

$\sf \mapsto \: 24 = 2x$

$\sf \mapsto \: x = \cancel \dfrac{28}{2}$

$\mathfrak \red{x = 14}$

Numbers are

$\tt \: x = 14$

$\tt \: x \: + 8 = 14 + 8 = 22$

Answer 2

To Find:-

• Find the two numbers.

Given:-

• The sum of two numbers is 36.
• One number exceeds another by 8.

Solution:-

First number = " x "

Second number = " x + 8 "

According to the question:-

$\tt\implies \: x + x + 8 = 36$

$\tt\implies \: 2x + 8 = 36$

$\tt\implies \: 2x = 36 - 8$

$\tt\implies \: 2x = 28$

$\tt\implies \: x = \cancel\dfrac{28}{2}$

$\tt\implies\boxed {x = 14}$

So,

$\tt The \: first \: number = 14$

$\tt The \: second \: number is 14 + 8 = 22$