Question

The sum of two numbers is 36. The numbers are such that one of them is 5 times the other number. Find the numbers
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Answer 1

From your question we infer the following two equations:

x+y = 36

x = 5y

Substitute for x in the first equation:

x + y = 36

x = 5y

5y + y = 36

Combine like terms:

6y = 36

Divide both sides by 6:

y = 6

So if y = 6, and x = 5y, then x = 30

Now substitute for both x and y in both of the original equations to prove they are the correct values.

x + y = 36

x = 30

y = 6

30+6= 36

36 = 36

x = 5y

x = 30

y = 6

30= 5*6

30=30

So the two numbers, x and y, are 30 and 6

respectively.

Answer 2

$\huge{\blue{\boxed{\boxed{\red{\underline{\green{\mathscr{Answer:}}}}}}}}$

The numbers are 30 and 6.

Step-by-step explanation:

Given :-

• Sum of 2 numbers = 36
• One number = 5 times more than other number

To Find :-

• Values of both the numbers

Solution :-

➠ Let the smaller number be x,

➠ Other number = 5x

Equation Formed:

⇒ 5x + x = 36

⇒ 6x = 36

⇒ x = $\frac{36}{6}$

⇒ x = 6

So, the numbers are:

$\underline{x}$ = ${\boxed{\purple{6}}}$

$\underline{5x}$ = 5 × 6 = ${\boxed{\purple{30}}}$

Verification :-

↦ 5x + x = 36

Put x = 6 we get,

↦ 30 + 6 = 36

➙ 36 = 36

➦ LHS = RHS

Hence, Verified ✔