Question

The sum of two numbers is 37. find the numbers if one number is 1 more than twice the other...​

Answer 1

Answer:

let number. x

other number 2x + 1

A.T.Q

2X+1 +X = 37

3X+1 =37

3X= 37-1

3X = 36

X =36 ÷ 3

X= 12

FIRST NO. =X =12

SECOND NO. = 2X +1 = 2×12 +1 = 25