The sum of two numbers is 384 and their HCF is 48. Find the two possible numbers.
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see the picture above
answer 288
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Answer:
Let the two numbers be 48x and 48y respectively where x and y are co-primes.
here,
384 = 48x + 48y
384 = 48(x + y)
384/48 = x + y
Hence, x+y=8
So, values of (x, y) = (1, 7) and (3, 5) only because they have to be co-primes.
Therefore , Possible numbers are: (48,336)
and (144,240).
Hence, The difference between the two numbers are:
288 and 96
I hope it clears your doubt.
Thanks
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