Question

The sum of two numbers is 40.one number is 10 more than the other. What are the numbers?

Answer 1

Answer:

15

Step-by-step explanation:

let smaller no. be x

then larger no.=x+10

their sum=40

therefore putting in the values

x+(x+10)=40

2x+10=40

2x=40-10

2x=30 sending two that side in division

x=30/2

x=15

hope it helps you if it is then Mark me the brainliest please

Answer 2

$GIVEN :$

$sum \: of \: the \: numbers \: is \: 40$

$one \: of \: the \: number \: is \: 10 \: more \: \\ than \: the \: other \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$SOLUTION:$

$let \: the \: first \: number \: be \: x$

$so \: the \: other \: number \: is \: x + 10$

☞$according \: to \: question \: \\ (x + x + 10) = 40 \: \: \: \: \: \: \: \: \:$

☞$2x + 10 = 40$

☞$2x = 40 - 10$

☞$2x = 30$

☞$x = \frac{30}{2} = 15$

$\boxed{So ,\: the \: first \: number\: is \:15 }$

$another \: number \: is \: 10 + x = 10 + 15 = 25$

$\boxed{ANSWER: \: The \: numbers\: are \: 15 \: and\: 25 }$

$Hope\: this \: help\: you$