the sum of two numbers is 4000. 10% of one number is 6whole2/3% of the other . the difference of the number is.
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let the first number be x
second number is 4000-x
10%of x =(20/3)%of (4000-x)
10x/100=(20/3)/100 *(4000-x)
10x*3/20=4000-x
3x/2=4000-x
3x=8000-2x
5x=8000
x=1600
first number is 1600
second number is 2400
difference of the numbers is 2400-1600=800
second number is 4000-x
10%of x =(20/3)%of (4000-x)
10x/100=(20/3)/100 *(4000-x)
10x*3/20=4000-x
3x/2=4000-x
3x=8000-2x
5x=8000
x=1600
first number is 1600
second number is 2400
difference of the numbers is 2400-1600=800
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