Question

the sum of two numbers is 4000.If 15% of one is equal to 25% of the other,find the numbers

Answer 1

hello users ...

Solution:-
let first number = x 
And
second number = y

According to question :
sum of two numbers is 4000.
=> x + y = 4000
=> x = 4000 - y   ........(1.)

And
15% of one is equal to 25% of the other
=> 15 % of x = 25 % of y 

=> 15x /100 = 25y/100

=> 3x/20 = y/4 

=> 12x = 20y  (cross multiply ...)

= 12x - 20y = 0  .........(2.)

putting value of x from equation (1.) in equation (2.)
we get
=> 12×(4000 - y) - 20y = 0 

=> 48000 - 12y - 20y = 0 

=> 48000 - 32y = 0 

=> 32y = 48000 

=> y = 1500 

Now, 
putting value of y in equation (1.)
we get
x = 4000 - y
=> x = 4000 - 1500

=> x = 2500 

Hence;
first number =x =  2500 
And
second number = y = 1500 Answer 

# Hope it helps 

:)

Answer 2

Step-by-step explanation:

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