Question

the sum of two numbers is 4000. If 4% of a number is equal 12% of other. Find the number.
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Answer 1

Step-by-step explanation:

Let the value of unknown numbers being (X) and (Y)

ATQ, X+Y= 4000

In the question condition is given that:

4% of X = 12% of Y

So, Let us think that the value of Y=1

So, 12% of Y = 12/100×1

= 3/25×1

= 3/25

= 0.12

According to condition (ATC), 4% of X= 0.12

So, Value of X= 4/100×X=0.12

= X= 0.12× 25

= X=3

So, 3x+1y= 4000

(ATC,4%X=12%Y)

=XY=4000/3+1

=XY=4000/4

=XY=1000

So, 3X= 3×1000

=3000

and, 1Y= 1×1000

=1000