Question

The sum of two numbers is 41. One number is less than twice the other. How do you find the larger of the two numbers?

Answer 1

let x+y=41

x<2y

x/2<y

x/2<41-x

x<82-2x

3x<82

x<82/3

x<27.33

x=27

y=14

the larger of the two numbers=27