the sum of two numbers is 42 and their difference is 24 then smaller of those two number is
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Solution
Given :-
- the sum of two numbers is 42
- their difference is 24
Find :-
- Those two number
Step - by - Step - Explanation
Let,
- First Number = x
- Second Number = y
A/C to question,
➡ x + y =42 _________(1)
Again,
(Their difference is 24)
➡ x - y = 24 _________(2)
Add equ(1) & equ(2)
➡ 2x = 42 + 24
➡2x = 66
➡x = 66/2
➡x = 33
Keep in equ(1) ,
➡33 + y = 42
➡y = 42 - 33
➡y = 9
Hence
- First Number be (x) = 33
- Second Number be(y) = 9
_______________
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