Question

the sum of two numbers is 42 and their difference is 24 then smaller of those two number is​ Solution

Answer 1

Answer:

Given :-

the sum of two numbers is 42

their difference is 24

Find :-

Those two number

Step - by - Step - Explanation

Let,

First Number = x

Second Number = y

A/C to question,

➡ x + y =42 _________(1)

Again,

(Their difference is 24)

➡ x - y = 24 _________(2)

Add equ(1) & equ(2)

➡ 2x = 42 + 24

➡2x = 66

➡x = 66/2

➡x = 33

Keep in equ(1) ,

➡33 + y = 42

➡y = 42 - 33

➡y = 9

Hence

First Number be (x) = 33

Second Number be(y) = 9

_______________

Answer 2

Step - by - Step - Explanatio

Let,

First Number = x

Second Number = y

A/C to question,

➡ x + y =42 _________(1)

Again,

(Their difference is 24)

➡ x - y = 24 _________(2)

Add equ(1) & equ(2)

➡ 2x = 42 + 24

➡2x = 66

➡x = 66/2

➡x = 33

Keep in equ(1) ,

➡33 + y = 42

➡y = 42 - 33

➡y = 9

Hence

First Number be (x) = 33

Second Number be(y) = 9