Question

the sum of two numbers is 42 and their difference is 24 then smaller of those two number is​ Solution Given :- the sum of two numbers is 42 their difference is 24 Find :- Those two number Step - by - Step - Explanation Let, First Number = x Second Number = y A/C to question, ➡ x + y =42 _________(1) Again, (Their difference is 24) ➡ x - y = 24 _________(2) Add equ(1) & equ(2) ➡ 2x = 42 + 24 ➡2x = 66 ➡x = 66/2 ➡x = 33 Keep in equ(1) , ➡33 + y = 42 ➡y = 42 - 33 ➡y = 9 Hence First Number be (x) = 33 Second Number be(y) = 9 _______________

Answer 1

Answer:

it's very simple 9

x+y=42 ( I took first equation)

33+y= 42

:: 42-33 =y

y=9