Question

The sum of two numbers is 43. If the difference between six times the smaller one twice the larger one is 2 find the two numbers

Answer 1

Answer:

x+y=43

6(x-y)...............

Answer 2

Answer:

hope you like the answer please mark me as brainlist

Step-by-step explanation:

1 and 32

Let the smaller number be x and the larger number be y.

Then we have x + y = 43 and 6x − 2y = 2.

x + y = 43 ------- (1)

6x − 2y = 2 i.e 3x − y = 1 ------- (2)

Adding (1) and (2), we get,

4x = 44

x = 11

So, y = 43 − 11 = 32

We can see that 11 + 32 = 43 and (6 × 11) − (2 × 32) = 2.