the sum of two numbers is 43.the differance is 13 find the numbers
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Answered by
1
Answer:
let the numbers be x and y.
their sum is 43, so x + y =43 .
their difference is 13, so x - y = 13.
on adding above equations, we get
x +y +x -y = 43+13
2x = 56
x = 56/2
x = 28.
then,
x+y =43
28+y =43
y=43-28
y= 15.
Hence, the numbers are 28 and 15.
Answered by
1
Answer:
The numbers are 28 and 15
Step-by-step explanation:
Let the numbers be a and b
=a+b=43
Their difference = 13
=a-b=13
To find the numbers we need to add the sum and the difference
=a+b+a-b=43+13
=a+b+a-b=56
=2a=56
=a=56/2=28/1
=a=28
To find b we need to use the main equation
Which is a+b=43
a+b=43
=28+b=43
=b=43-28
=b=15
Therefore b=15
Thus,
The numbers are 28 and 15
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