Question

The sum of two numbers is 44. If one of the numbers

is 10 more than the other, then what are the numbers?​

Answer 1

Answer:

17 and 27

Step by step explaination:

(10+x) + x=44

10× + x=44

2x=44-10=34

x=34/2

x=17

10+×=17+10= 27

hope it will help you ✌✌

Answer 2

Given:

• The sum of two numbers is 44. And, one of the numbers is 10 more than the other number.

To find:

• The numbers.

Solution: Let the required number be x and second Number be (10 + x) respectively.

A/Q,

• The sum of two numbers is 44. And, one of the numbers is 10 more than the other one. Therefore,

★ First no. + Second no. = Sum of the numbers ★

$\implies$ (10 + x) + x = 44

$\implies$ 10 + 2x = 44

$\implies$ 2x = 44 - 10

$\implies$ 2x = 34

$\implies$ x = 34/2

$\implies$ x = 17 ★

➠ Second no. = (10 + x)

➠ Second no. = 10 + 17

➠ Second no. = 27 ★

•°• Hence, the required Numbers are 17 and 27 respectively.

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★ VERIFICATION :

• We're given with the sum of both the number that is 44. Let's verify both the numbers. Therefore,

➠ (First no.) + (Second no.) = 44

➠ 17 + 27 = 44

➠ 44 = 44

⠀⠀⠀⠀⠀$\therefore$ Hence Verified!