Question

The sum of two numbers is 45 and their ratio is 7:8. The two numbers are

Answer 1

$let \: the \: sum \: of \: number \: are \: in \: the \: ratio \: be \: x \\ \\ 1st \: no. = 7x \\ \\ 2nd \: \: no. = 8x \\ \\ sum \: of \: a \: number \: is \: 45 \\ \\ 7x + 8x = 45 \\ \\ 15x = 45 \\ \\ x = \frac{45}{15} \\ \\ x = 3 \: \: \\ \\ 1st \: no. = 7x = 7 \times 3 = 21 \\ \\ 2nd \: \: no. = 8x = 8 \times 3 = 24 \: \: \: \: \: \: answer \: \: \\please \: \: mark \: \: me \: \: as \: \: brainliest \:$

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Answer 2

$\bf \large \it{Hey \: User!!!}$

according to the question, two numbers are in ratio 7 : 8 and their sum is 45.

let the two numbers be 7x and 8x

therefore 7x + 8x = 45
>> 15x = 45
>> x = 45/15
>> x = 3

hence, the numbers are :-

7x = 7 × 3 = 21 and 8x = 8 × 3 = 24

$\bf \large \it{ Cheers!!!}$