The sum of two numbers is 45. Their difference is 1/9 of their sum. find their Lcm..
Answers
Answered by
60
Let the two numbers be x, y.
x + y = 45 ---> EQ1.
x - y = 1/9(45)
x - y = 5 ---> EQ2.
Solve the two equations.
2x = 50
x = 25
Put x = 25 in EQ1.
25 + y = 45
y = 20
So, the two numbers are 20, 25 and their LCM is 100.
x + y = 45 ---> EQ1.
x - y = 1/9(45)
x - y = 5 ---> EQ2.
Solve the two equations.
2x = 50
x = 25
Put x = 25 in EQ1.
25 + y = 45
y = 20
So, the two numbers are 20, 25 and their LCM is 100.
khushikumari11:
hey lcm means least common number
30 = 2 × 3 × 5
45 = 3 × 3 × 5
Then multiply each factor the greatest number of times it occurs in either number.
2: one occurrence
3: two occurrences
5: one occurrence
2 × 3 × 3 × 5 = 90 <— LCM
Answered by
11
let first no=x
and second=y
therefore x+y=45 ................equ 1
and x-y=45×1/9
=5..........equ 2
from equ 1 and 2 we have -
x=25 and=20
the L.C.M of 25 and 20 is
25=5×5
20=2×2×5
therefore lcm (25 and 20)=5 ans THANKS
and second=y
therefore x+y=45 ................equ 1
and x-y=45×1/9
=5..........equ 2
from equ 1 and 2 we have -
x=25 and=20
the L.C.M of 25 and 20 is
25=5×5
20=2×2×5
therefore lcm (25 and 20)=5 ans THANKS
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