Question

The sum of two numbers is 4500.If 10%of one number is 12.5%of the other, Find the numbers

Answer 1

Let the two numbers are x and y.
According to the question, 10% of one number is 12.5% of the other.
So, 10% of x =12.5% of y
1/10 of x=125/1000 of y
1/10 of x=1/8 of y
x=1/8÷1/10of y
x=1/8×10of y
x=10/8=5/4 of y
Now, x+y=4500
5/4 of y+y=4500
( 5/4+1)of y=4500
9/4 of y=4500
y=4500×4/9=500×4=2000
x=5/4 of y=5/4×2000=2500
Hence,the two numbers are 2000 & 2500.

Answer 2

let one number be x
then the other number is 4500-x
atq(according to question)
12.5x/100=10/100(4500-x)
12.5x/100=450-10x/100
22.5x/100=450
x=(450*100)/22.5
  =2000
hence, one number  2000
the other number is 4500-2000=2500