Question

The sum of two numbers is 46 and their difference is 28. Find the smaller and the bigger number

Answer 1

Answer:

Larger number (x) = 37

Smaller number (y) = 9

Step-by-step explanation:

Let the larger number be x and smaller number be y.

x+y = 46 ---------------------(1)

x-y = 28 ---------------------(2)

By elimination method, Add (1) and (2)

x+y = 46

x-y = 28

----------------------------------------------

2x = 74

x = 37

Substitute x= 37 in eqn.(1)

37 + y = 46

y = 46 - 37

y = 9.

Therefore,

Larger number (x) = 37

Smaller number (y) = 9

Answer 2

Answer:

Step-by-step explanation:

Let one of the number be $x$ and the other be $y$

Now, x+y= 46   ---1

        x-y = 28   ---2

Adding 1 and 2

$x+y+x-y= 46+28\\2x= 74\\x= 37$

Now,

$y= 46-x\\y= 46-37\\y= 9$

So, $x= 37 y=9$