The sum of two numbers is 48 and the difference is 20 . What are the numbers?
Answers
Answer:
The sum of two numbers is 48 and their difference is 20. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 48. In other words, x plus y equals 48 and can be written as equation A:
x + y = 48
The difference between x and y is 20. In other words, x minus y equals 20 and can be written as equation B:
x - y = 20
Now solve equation B for x to get the revised equation B:
x - y = 20
x = 20 + y
Then substitute x in equation A from the revised equation B and then solve for y:
x + y = 48
20 + y + y = 48
20 + 2y = 48
2y = 28
y = 14
Now we know y is 14. Which means that we can substitute y for 14 in equation A and solve for x:
x + y = 48
x + 14 = 48
X = 34
Summary: The sum of two numbers is 48 and their difference is 20. What are the two numbers? Answer: 34 and 14 as proven here:
Sum: 34 + 14 = 48
Difference: 34 - 14 = 20
Answer:
let the numbers are x, y
x+y = 48
x-y =20
x=20+y
x+y=48
20+y+y=48
20+2y=48
2y = 48
y = 14
x+y = 48
x+14 = 48
x =34
hope it helps u dear!!