Question

The sum of two numbers is 48 and their product is 432 find the number

Answer 1

Answer:

therefore the reqd numbers are 12 and 36

Answer 2

Solution

Let required number be X and Y.

Then, accounting to question

$x + y = 48$

$➽y = 48 - x \: \: \: ...(1)$

Again according to question,

$x.y = 432$

$➽x(48 - x) = 432 \: \: \: {from \: eqn.(1)}$

$➽48x - {x}^{2} = 432$

$➽ {x}^{2} - 48x + 432 = 0$

$➽ {x}^{2} - 36x - 12x + 432 = 0$

$➽x(x - 36) - 12(x - 36) = 0$

$➽(x - 36)(x - 12) = 0$

$➽x - 36 = 0 \\ \\ or \\ x - 12 = 0$

$➽x = 36 \\ or \\ x = 12$

Therefore first number X = 36, then second number = 48 - 36 = 12,

And If first number X = 12, then second number = 48 - 12 = 36