Question

The sum of two numbers is 48. If the smaller number
is one fifth of the larger number, find the two numbers.​

Answer 1

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Let x = smaller number

y = larger number

"their sum is 48" means x + y = 48 [eq1]

"smaller number is equal to one-fifth of the larger number" means x = (1/5)y [eq2]

Elimination method:

x + y = 48 [eq1]

5x - y = 0 [from eq2]

-------------------- [elimination; add equations]

6x = 48

x = 8

x + y = 48 [eq1]

------------------- [elimination; subtract two equations]

- y = - 40

y = 40 [divide by (-1)]

$\mathcal\red{ I \: hope \: it \: helps \: u}$

Answer 2

Step-by-step explanation:

x+y=48

smaller angle =x

larger angle=y

x=1/5y

x+1/5y=48

x=48-1/5y

x=239/5y

239/5y+y =48

6y+239/5y=48

245/y=48×5

y=240/245