The sum of two numbers is 49 and their difference is 13. What is the larger number?
Answers
Answer :-
- The larger number is 31.
Step-by-step explanation:
To Find :-
- The larger number
Solution:
Given that,
- The difference between two numbers is 13
- The sum of two numbers = 49
Assumption: Let us assume one number as x and the other number as ( x - 13 ),
Therefore,
- x + ( x - 13 ) = 49
=> x + ( x - 13 ) = 49
=> x + x - 13 = 49
=> x + x = 49 + 13
=> x + x = 62
=> 2x = 62
=> x = 62/2
=> x = 31
Hence, The value of x is 31.
Now, The numbers are :-
- The number which we assumed as x
=> x
=> 31
- The number which we assumed as ( x - 13 )
=> ( x - 13 )
=> ( 31 - 13 )
=> 18.
According the question,
The larger number is :-
=> 31 > 18
So, The larger number is 31.
..QUESTION..
The sum of two numbers is 49 and their difference is 13 . What is the larger number ?
..ANSWER..
Given ,
ㅤㅤ➪ Sum of the numbers = 49ㅤ --(1)
ㅤㅤ➪ Difference "ㅤ" ㅤ"ㅤ= 13ㅤ --(2)
★ Let the numbers are
•°• ㅤㅤㅤFirst number = x
ㅤㅤㅤSecond number = x - 13
•°• In equation 1
➪ 1st number + 2nd number = 49
ㅤㅤㅤ➪ x + ( x - 13 ) = 49
ㅤㅤㅤ➪ x + x - 13ㅤ = 49
ㅤㅤㅤ➪ 2x - 13 ㅤ = 49
ㅤㅤㅤ➪ㅤ2xㅤㅤㅤ = 49 + 13
ㅤㅤㅤ➪ㅤ2x ㅤㅤㅤ= 62
ㅤㅤㅤ➪ㅤxㅤㅤㅤㅤ= 62 / 2
ㅤㅤㅤ➪ㅤxㅤ ㅤ ㅤ = 31
°•° First number ➪ x = 31
•°• Second number ➪ x - 13
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➪ 31 - 13
ㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➪ 18
•°• Larger number = 1st number = 31 ✓
ㅤㅤㅤㅤㅤ★VERIFICATION★
☯︎ From ( 1 )
ㅤ➪ sum of the numbers = 49
ㅤ➪ 1st number + 2nd number
ㅤ➪ㅤ31ㅤ+ㅤ18
ㅤ➪ㅤ49ㅤ=ㅤR.H.S
☯︎ From ( 2 )
ㅤ➪ Difference of numbers = 13
ㅤ➪ 1st number - 2nd number
ㅤ➪ㅤ31ㅤ-ㅤ18
ㅤ➪ㅤ13ㅤ=ㅤR.H.S