The sum of two numbers is 5 and difference of their squares is 5 . Find the difference of the numbers.
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Answered by
37
Let the numbers be x and y
X+y = 5
X^2-y^2=5
(X+y)(x-y)=5
5(x-y)=5
X-y=5 /5
X-y =1
Therefore the difference between the two numbers is 1
X+y = 5
X^2-y^2=5
(X+y)(x-y)=5
5(x-y)=5
X-y=5 /5
X-y =1
Therefore the difference between the two numbers is 1
Answered by
79
Let the two numbers be x and y.
Given that sum of two numbers is 5.
= > x + y = 5 ----- (1)
Given that Difference of their squares is 5.
= > x^2 - y^2 = 5
We know that a^2 - b^2 = (a + b)(a - b)
= > (x + y)(x - y) = 5
= > (5)(x - y) = 5
= > (x - y) = 1.
Therefore, the difference of the numbers = 1.
Hope this helps!
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