the sum of two numbers is 50 and the difference is 30 form an equation x and find the number.
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Let the two numbers be x, y.
x+y = 50 [Eq 1]
x-y = 10 [Eq 2]
x = 50-y [From Eq - 1]
Substitute this value in Eq 2
x-y = 10
50-y -y = 10 [Add two negative numbers and assign a - sign]
50–2y = 10 [As numbers are transposed from one to another side their sign changes]
50 -10 = 2y
40 = 2y
Dividing by 2 both sides
40/2 = 2y/2
20 = y
x = 50-y
x = 50–20 = 30
x = 30, y = 20 :Final Answer
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