Question

The sum of two numbers is 51.l.c.m of two numbers is 168.find two mubers

Answer 1

Step-by-step explanation:

Let h be the HCF of two numbers. Let the two numbers be ha and hb.

Given, sum of numbers is 52

ha + hb = 52

h(a + b) = 52

LCM × HCF = Product of Numbers = ha × hb

168 × h = ha × hb

hab = 168

Calculating, we get

h = 4, a = 7 and b = 6

So the numbers ha and hb are 28 and 24.

Answer 2

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Let h be the HCF of two numbers.

Let the two numbers be ha and hb.

Given,

sum of numbers is 52

ha + hb = 52

h(a + b) = 52

LCM × HCF = Product of Numbers = ha × hb=168 × h = ha × hb = 168

Calculating,

we get

h = 4, a = 7 and b = 6

So the numbers ha and hb are 28 and 24.

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sum is 52 not 51

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Additional information ⏬

• LCM : The least number which is exactly divisible by each of the given numbers is called the least common multiple of those numbers
• HCF : The largest number that divides two or more numbers is the highest common factor (HCF) for those numbers.

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