Question

The sum of two numbers is 51 the larger number is 19 more than the smaller number what are the numbers

Answer 1

Answer:

$let \: \: \: the \: \: \: small \: \: \: number \: \: \: be \: \: \: x \\ \\ s \: \: \: the \: \: \: bigger \: \: \: number \: \: \: would \: \: \: be \: \: \: x + 19 \\ \\ \\ as \: \: \: per\: \: \: the \: \: \: given \: \: \: \: condition \: \: \\ \\ x + x + 19 = 51 \\ \\ 2x + 19 = 51 \\ \\ 2x = 51 - 19 \\ \\ x = \frac{42}{2} = 21 \\ \\ so \: \: \: \: x = 21$

Answer 2

Given :-

• The sum of two numbers is 51 the larger number is 19 more than the smaller number

To Find :-

• Numbers

Solution :-

⟼ Let the First Number be x

⟼ Then Second Number will be x + 19

According to the Question :

➞ Sum of Numbers = 51

➞ x + x + 19 = 51

➞ x + x = 51 - 19

➞ x + x = 32

➞ 2x = 32

➞ x = 32 / 2

➞ x = 16

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Therefore :

• First Number = x = 16
• Second Number = x + 19 = 16 + 19 = 35

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