Question

The sum of two numbers is 53 and the difference is 14.5. What is the digit at the units place of the smaller number.​

Answer 1

Answer:

9

Explanation:

Let the numbers be x and y.

According to the question,

$\rm \bullet \: Sum \:o f \: the \: numbers : - \\ \rm \: \implies \: x + y = 53\bf . . . . (i)$

$\rm \bullet \: Difference \:o f \: the \: numbers : - \\ \rm \: \implies \: x - y = 14.5\bf . . . . (ii)$

Subtracting eq. (i) by (ii) :-

$\rm \: \: \: \: \: x + y = 53 \\ \tiny{( - )} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \rm{ \: \: \: \: \underline{x - y = 14.5}} \\ \rm \implies \: 2y = 38.5\\ \rm \implies \:y = \dfrac{38.5}{2} \\ \rm \implies \:y = 19.25$

Substituting ‘y’ in eq.(i) :-

$\rm \implies \:x + y = 53$

$\rm \implies \:x + 19.25 = 53$

$\rm \implies \: x = 53 - 19.25$

$\rm \implies \: x = 33.75$

Hence, the numbers are 19.25 and 33.75

Digit at the unit place of smaller number i.e., 19.25 is 9

Answer 2

Let one number be x and another be y

Given, x+y =53........... (1)

x-y =14.5......... (2)

By adding equation 1 and equation 2, we get–

x+y+x-y =53+14.5

or, 2x =67.5

or, x=67.5/2

or, x=33.75

• Now substituting the value of x in equation 1, we get —

33.75+y =53

y =53-33.75

y = 19.25

Ans:- 9 is the unit place digit.