Question

the sum of two numbers is 56 and one of them is 8 less than the other.what is the smaller number​

Answer 1

Answer:

24

Step-by-step explanation:

Let x = larger # and x-8 = smaller number

(x) + (x-8) = 56

2x - 8 = 56

2x = 64

x = 32  (larger #)

32 - 8 = 24

Answer 2

Answer:

Let 1st no. be x

then 2nd no. =x-8

A/Q

x+x-8=56

2x=56+8

2x=64

x=32

Thus ,1st no. is 32

and 2nd no. is (32-8)=24

Hope it will help you