The sum of two numbers is 56. If three times the
first number exceeds one-third of the second by 48.
The numbers are.
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Answer:
88/7 and 216/7
Step-by-step explanation:
x + y= 56 ....(1)
3x + y/3 = 48
9x + y = 144
y= 144 - 9x ....(2)
In Eq.1:- x + (144 - 9x) = 56
-7x + 144 = 56
7x = 144- 56
x =88/7
In Eq.2:- y = 144 - 9(88/7)
y = 216/7
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