Question

The sum of two numbers is 56. If three times the
first number exceeds one-third of the second by 48.
The numbers are.
​

Answer 1

Answer:

88/7 and 216/7

Step-by-step explanation:

x + y= 56 ....(1)

3x + y/3 = 48

9x + y = 144

y= 144 - 9x ....(2)

In Eq.1:- x + (144 - 9x) = 56

-7x + 144 = 56

7x = 144- 56

x =88/7

In Eq.2:- y = 144 - 9(88/7)

y = 216/7