Question

the sum of two numbers is 62.if one number is thrice the number the smaller number is​

Answer 1

Answer:

The answer is $\frac{31}{2}=15.5$

Step-by-step explanation:

Since sum of two number is 61, so let one number be $x$ and

other number be $62-x$.

Also given, one of these number is thrice of other

        $\Rightarrow 62-x=3x\\\Rightarrow 62=3x+x\\\Rightarrow 4x=62\\\Rightarrow x=\frac{62}{4}=\frac{31}{2}$

So other number is $=62-x=62-\frac{31}{2}=\frac{124-31}{2}=\frac{93}{2}$

Hence the smaller number is $\frac{31}{2}=15.5$

Answer 2

Answer:

The smallest number is $15.5$

Step-by-step explanation:

Assume two numbers $x\ and\ y$ such that $x+y=62$

given that one number is thrice of the other number , so assign $y=3x$

then, $x+3x=62$

implies $4x=62$

implies $x=62/4=15.5$.

Hence $x=15.5$ ,$y=46.5$.

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