Question

the sum of two numbers is 63. the first is 6 times the second. find the number

Answer 1

Let the numbers be x and y respectively.

Given

Sum of 2 numbers = 63

$\implies x+y=63$

The first number is 6 times the second number

$\implies x = 6y$

Substituting, x = 6y in the second equation, we get,

$\implies 6y+y=63$

$\implies 7y= 63$

$\implies y = \dfrac{63}{7}$

$\implies y =9$

Now,

$x+9=63$

$\implies x = 63-9$

$\implies x = 54$

$\boxed{\boxed{\bold{Therefore, \ the \ two \ numbers \ are \ 9 \ and \ 54}}}}}}$

                                                       

Answer 2

Answers

let the first number be x

ATQ:

second number = x/6

x + x/6=

6x=x/6=63

7x/6=63

x=54 and second number = 9