Question

The sum of two numbers is 64, and the second number is 16 less than the first. Find the
numbers. One number is 7 times another. If 14 is added to the sum of the numbers, the
result is 38. Find the number​

Answer 1

Answer:

Let one number be x and other yx+y=64y=x-16putting value of y in eq. 1x+x-16=642x=80x=40y=40-16=24

Step-by-step explanation:

futher do yourself.......

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