The sum of two numbers is 64, and the second number is 16 less than the first. Find the
numbers. One number is 7 times another. If 14 is added to the sum of the numbers, the
result is 38. Find the number
explain the answer
Answers
Answer:
Answer:Let one number be x and other yx+y=64y=x-16putting value of y in eq. 1x+x-16=642x=80x=40y=40- ...
QUESTION 1:
The sum of two numbers is 64, and the second number is 16 less than the first. Find the numbers.
ANSWER:
- The numbers are 40, 24.
GIVEN:
- The sum of two numbers is 64.
- The second number is 16 less than the first number.
TO FIND:
- The two numbers.
EXPLANATION:
Let the numbers be x and y.
x + y = 64
y = x - 16
Substitute y = x - 16 in x + y = 64
x + x - 16 = 64
2x - 16 = 64
2x = 80
x = 40
Substitute x = 40 in y = x - 16
y = 40 - 16
y = 24
Hence the numbers are 24 and 40.
VERIFICATION:
Substitute x = 40 and y = 24 in y = x - 16
24 = 40 - 16
24 = 24
Substitute x = 40 and y = 24 in x + y = 64
40 + 24 = 64
64 = 64
HENCE VERIFIED.
QUESTION 2:
One number is 7 times another. If 14 is added to the sum of the numbers, the result is 38. Find the numbers.
ANSWER:
- The numbers are 3, 21
GIVEN:
- One number is 7 times another.
- If 14 is added to the sum of the numbers, the result is 38.
TO FIND:
- The two numbers.
EXPLANATION:
Let the numbers be a and b.
a = 7b
a + b + 14 = 38
a + b = 24
Substitute a = 7b in a + b = 24
7b + b = 24
8b = 24
b = 3
Substitute b = 3 in a = 7b
a = 7(3)
a = 21
Hence the numbers are 3 and 21.
VERIFICATION:
Substitute a = 21 and b = 3 in a = 7b
21 = 7(3)
21 = 21
Substitute a = 21 and b = 3 in a + b + 14 = 38
21 + 3 + 14 = 38
24 + 14 = 38
38 = 38