Question

The sum of two numbers is 64, and the second number is 16 less than the first. Find the
numbers. One number is 7 times another. If 14 is added to the sum of the numbers, the
result is 38. Find the number​

explain the answer​

Answer 1

Answer:

let the no be x and y

x+y=64

y = x - 16

putting the value of y in equation 1.

x+x-16=64

2x=64+16

2x=80

x=80/2

x=40

y=40-16

y=24

Step-by-step explanation:

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Answer 2

Questions

1. The sum of two numbers is 64, and the second number is 16 less than the first. Find the numbers.

2. One number is 7 times another. If 14 is added to the sum of the numbers, the result is 38. Find the number​

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Answers

1. The first number would be ⇒ x

The second number would be ⇒ x - 16

So our equation now would be ⇒ $x+x-16=64$

Let's solve your equation step-by-step.

$x+x-16=64$

Step 1: Simplify the equation.

$x+x-16=64$

$2x-16=64$

Step 2: Add 16 to both sides of the equation.

$2x-16+16=64+16$

$2x=80$

Step 3: Divide 2 from both sides of the equation.

$\frac{2x}{2} =\frac{80}{2}$

$x=40$

∴The first number would be ⇒ 40

∴The second number would be ⇒ 40 - 16 = 24

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2. The first number would be ⇒ y

The second number would be ⇒ 7y

So our equation now would be ⇒ $y+7y+14=38$

Let's solve your equation step-by-step.

$y+7y+14=38$

Step 1: Simplify the equation.

$y+7y+14=38$

$8y+14=38$

Step 2: Subtract 14 from both sides of the equation.

$8y+14-14=38-14$

$8y=24$

Step 3: Divide 8 from both sides of the equation.

$\frac{8y}{8}=\frac{24}{8}$

$y=3$

∴The first number would be ⇒ 3

∴The second number would be ⇒ 7 × 3 = 21

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