Question

The sum of two numbers is 64, and the second number is 16 less than the first Find the numbers.
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Answer 1

let one number be x and other be y

x + y = 64(given)

y= x-16(eq1)

x+(x-16) = 64

2x = 64 + 16 = 80

x=80/2

therefore, x = 40 and y = (40 - 16)= 24

X= 40 y= 24

Answer 2

Answer:

1ST NUMBER = 40

2ND NUMBER = 24

EXPLANATION BELOW↓↓↓

Step-by-step explanation:

SUM OF TWO NUMBERS = 64

LET THE FIRST NUMBER BE X

SO, THE SECOND NUMBER BE X - 16

A/Q,

=} X + X - 16 = 64

=} 2X - 16 = 64

=} 2X = 64 + 16

=} 2X = 80

=} X = 80

2

=} X = 40 ( 80 GETS CANCELLED BY 2 RESULTING IN 40 )

THEREFORE ,

FIRST NUMBER

=} X = 40

SECOND NUMBER

=} X - 16

=} 40 - 16

=} 24

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