Question

the sum of two numbers is 64 and the second number is 16 less than the first find the numbers​

Answer 1

Answer:

40,24

Step-by-step explanation:

let assume the no. be x

first no. = x

second no. =x-16

according to the question,

x+x-16=64

2x=64+16

x=80÷2

x=40

hence first no. is 40

second no is 40-16 = 24

HOPE IT HELPS

Answer 2

Answer:

let first number=x

second=x-16

sum of two numbers=x+x-16=64

2x-16=64

2x=64+16

2x=80

x=80/2

x=40

first number=40

second number =40-16=24