The sum Of two numbers is 64, and the second number is 16 less than the first. Find the number
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Answer:
x + y = 64
x = y - 16
(y - 16) + y = 64
2y -16 = 64
2y = 80
y = 40
y=40
Solve for x:
x = y - 16
x = 40 - 16
x = 24
x = 24,y=40
The two numbers are 24 and 40.
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