The sum of two numbers is 67 if one exceed the other by 3 find the numbers
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The sum of two numbers is 67, if one exceed the other by 3 find the numbers.
Let first number be = 'x'
Let second number be = 'x+3'
Their sum = 67
A.T.Q.
x+x+3 = 67
2x+3 = 67
2x = 67-3
2x = 64
x = 64/2
x = 32
First number = x = 32
Second number = x+3 = 32+3 = 35
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