The sum of two numbers is 68.When the larger number is divided by the smaller one, we get 2 as
quotient and 5 as remainder. Find the numbers.
Answers
Step-by-step explanation:
let 68-x = Larger Number
x = Smaller Number
The sum of two no. is 68.
68-x + x = 68
When the larger no. is divided by the smaller one, we get 2 as quotient and 5 as remainder.
(68-x)/x = (2)+(5/x)
(68-x)/x = (2x/x)+(5/x)
Multiply both side by x
68-x = 2x+5
63 = 3x
21 = x
Substitute x for 21
68 - 21 = 47
The Larger number is 47 while the smaller number is 21.
Check
47 + 21 = 68
47/21 = 2 remainder 5
Step-by-step explanation:
Let 68-x = Larger Number
x = Smaller Number
The sum of two no. is 68.
68-x + x = 68
When the larger no. is divided by the smaller one, we get 2 as quotient and 5 as remainder.
(68-x)/x = (2)+(5/x)
(68-x)/x = (2x/x)+(5/x)
Multiply both side by x
68-x = 2x+5
63 = 3x
21 = x
Substitute x for 21
68 - 21 = 47
The Larger number is 47 while the smaller number is 21.
Check
47 + 21 = 68
47/21 = 2 remainder 5