The sum of two numbers is 7038. If one of the addends is 4832 greater than the other addend, what is the value of the larger addend.
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Answered by
4
let's consider 1 addend as x.
=> another addend =x+4832
=> x+x+4832=7038
=> 2x=7038-4832
=> 2x = 2206
=> x= 1103
therefore , larger addend= 1103+4832
= 5935
=> another addend =x+4832
=> x+x+4832=7038
=> 2x=7038-4832
=> 2x = 2206
=> x= 1103
therefore , larger addend= 1103+4832
= 5935
rockingmeet992:
hope this would help you
Answered by
1
HI
AIM : The sum of two numbers is 7038. If one of the addends is 4832 greater than the other addend, what is the value of the larger addenD
LET ONE NUMBER BE X
othe number
= x +4832
now,
x +x +4832 = 7038
2x + 4832 = 7038
2x = 7038 - 4832
2x = 2206
x = 2206/2
x =1103
other number = x + 4832
=> 1103 + 4832
=> 5935
so the larger addend is 5935
hope it helps u
:)
AIM : The sum of two numbers is 7038. If one of the addends is 4832 greater than the other addend, what is the value of the larger addenD
LET ONE NUMBER BE X
othe number
= x +4832
now,
x +x +4832 = 7038
2x + 4832 = 7038
2x = 7038 - 4832
2x = 2206
x = 2206/2
x =1103
other number = x + 4832
=> 1103 + 4832
=> 5935
so the larger addend is 5935
hope it helps u
:)
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