the sum of two numbers is 72.if one of the number is 6 more than the other.find the numbers
Answers
Answered by
154
Let one of the numbers be x.
So,other no.=6+x
sum of the numbers=72
x+6+x=72
2x+6=72
2x=72-6
2x=66
x=66/2
x=33
The numbers are 33 and 39.
So,other no.=6+x
sum of the numbers=72
x+6+x=72
2x+6=72
2x=72-6
2x=66
x=66/2
x=33
The numbers are 33 and 39.
Answered by
3
The two numbers are 33 and 39
Given:
The sum of two numbers is 72
One of the number is 6 more than the other
To find:
Find the numbers
Solution:
Let x and y be the two numbers
One of the number is 6 more than the other
Let's take y is 6 more than y
⇒ y = x + 6
Therefore, sum of x and x+6 is equals to 73
⇒ x + x + 6 = 72
⇒ 2x = 72 - 6
⇒ 2x = 66
⇒ x = 66/2 = 33
the value of x = 33
Then y = 33 + 6 = 39
Therefore, the two numbers are 33 and 39
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