Question

The sum of two numbers is 72. If one of the number is 6 more than the other, find the numbers,​

Answer 1

Answer:

The sum of two numbers is 72. One of the numbers is six more than twice the other. What are the two numbers?

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Let the two numbers be x and y.

As per statement, the sum of these two numbers is 72. Thus

x + y = 72…Eq.1

One of the numbers, x is six more than twice the other, means y. Thus

x = 2×y + 6 …Eq.2

Now putting the value of x from Eq.2 to Eq.1

x + y = 72

(2×y + 6) + y = 72

2y + 6 + , ya = 72

3y = 72 - 6

3y = 66

y = 22

Now putting the value of y from above in Eq..1

x + y = 72

x + 22 = 72

x = 72–22

x = 50

Thus two numbers are 50 and 22

Answer the two numbers are 50 and 22.

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Answer 2

${\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}$

$\mathfrak{\underline{AnswEr:-}}$

• Other number = 33
• One number = 39

$\mathfrak{\underline{Given:-}}$

• The sum of two numbers is 72.
• If one of the number is 6 more than the other.

$\mathfrak{\underline{Need\:To\: Find:-}}$

• Other number = ?
• One number = ?

${\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}$

Let the number be y.

$\:\:\:\:\dag\bf{\underline{\underline \red{Then:-}}}$

• One number = y + 6

$\boxed{\bf{\mid{\overline{\underline{\bigstar\: According\: to \: the \: Question :}}}}\mid}$

$\longrightarrow \sf {y + y + 6 = 72}$

$\longrightarrow \sf {2y + 6 = 72}$

$\longrightarrow \sf {2y = 72 - 6}$

$\longrightarrow \sf {2y = 66}$

$\longrightarrow\sf \:{y = \cancel\dfrac{66}{2} }$

$\longrightarrow \sf {y = 33}$

$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

• Other number = 33
• One number = 33 + 6
• One number = 39

$\rule{200}{2}$