Question

the sum of two numbers is 72.if one of the number is 6 more than the other ,find the numbers.

LET the numbers to be x.
the two numbers to be x.

= x+x+x+6 =72
=3x=72-6
3x=66
x=66/3
x=33
the first answer

=(33+6)
39
the second answer.​

Answer 1

Answer:

Let the First No. be x and Second no. I be x+6

A/Q,

x+x+6 = 72

2x = 72-6

X = 66/2

X = 33

Therefore, First No. = x = 33

second no. = x+6 = 33+ 6= 39

Step-by-step explanation:

In Question, it is given that sum of two numbers is 72. One number is 6 more than other number. So, Let first no. be x and second number be x+6.

Now, According to Question, we get x+x+6 = 72.

Answer 2

Answer:

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