The sum of two numbers is 72 if one of the number is 6 more than the others, find the numbers
Answers
Answered by
3
x+y=72 ,..(1)
x=y-6
x-y=-6 ...(2)
adding (1)$(2)
x+y=72
x-y=-6
x=33
y=39
x=y-6
x-y=-6 ...(2)
adding (1)$(2)
x+y=72
x-y=-6
x=33
y=39
Answered by
3
Answer:
33, 39
Step-by-step explanation:
Let one of the given numbers be x
∴ another number = x + 6 [ 6 more than the first one]
According to question
Sum of numbers = 72
x + (x +6) = 72
2x + 6 = 72
2x = 66
x = 33
Hence two numbers are 33 and 39 [x and x+6]
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