Question

The sum of two numbers is 72 if one of the number is 6 more than the others, find the numbers

Answer 1

x+y=72 ,..(1)
x=y-6
x-y=-6 ...(2)
adding (1)$(2)
x+y=72
x-y=-6
x=33
y=39

Answer 2

Answer:

33, 39

Step-by-step explanation:

Let one of the given numbers be x

∴ another number = x + 6    [ 6 more than the first one]

According to question

Sum of numbers = 72

x + (x +6) = 72

2x + 6 = 72

2x = 66

x = 33

Hence two numbers are 33 and 39 [x and x+6]