Question

the sum of two numbers is 74 the first number is 10 more then the other number what are the numbers​

Answer 1

Answer :-

• The first number is 42
• The second number is 32.

Step-by-step explanation:

Assumption:

Let us assume the first number ( 10 more than the other ) and the second number as (x+10) and (x) respectively.

Therefore,

• (x + 10) + (x) = 74

⇒ ( x + 10 ) + ( x ) = 74

⇒ x + 10 + x = 74

⇒ 2x + 10 = 74

⇒ 2x = 74 - 10

⇒ 2x = 64

⇒ x = 64/2

⇒ x = 32

The value of x is 32.

∴ The numbers are :-

• (x+10) = (32+10) = 42
• (x) = 32

Hence, The numbers are 42 and 32.

Now, Verification

• (x+10) + (x) = 74

Putting the value of numbers, [L.H.S] :-

⇒ (x+10) + (x)

⇒ 42 + 32

⇒ 74

Therefore, L.H.S and R.H.S = 72

Hence, Verified!

Answer 2

$\large {\frak {\underline {\dag \; \; Given :}}}$

• Sum of two numbers = 74
• First number is 10 more than the other.

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\large {\frak {\underline {\dag \; \; To \; find :}}}$

• Both the numbers.

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\large {\frak {\underline {\dag \; \; Let's \; Assume :}}}$

• Let the other number be x
• First number is 10 more than the other number. So, the number = x + 10

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

$\large {\frak {\underline {\dag \; \; Solution :}}}$

$\;\; \; \; \; \; \; \bigstar {\textbf {\textsf {\underline { According \; to \; the \; question :}}}}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎$: \implies \sf { (x + 10) + x = 74}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎$: \implies \sf { 2x + 10 = 74}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎$: \implies \sf { 2x = 74 - 10}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎$: \implies \sf { 2x = 64}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎$:\implies \sf { x = \dfrac {64}{2}}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎$: \implies \sf { x = 32}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎

Therefore,

ㅤ‎ㅤ‎ㅤ‎ㅤ‎$\to \sf { First ~number = x + 10 = 32+ 10 = 42}$

ㅤ‎ㅤ‎ㅤ‎ㅤ‎$\to \sf { Other ~ number = x = 32}$